I'm asked to use the transformation of v= 2xy to solve dy/dx = (2xy4)/ (4x2y 1) the answer given is (2/9)(6x3y2) (7/9)ln(6x3y2) = x c , i got (2/9)(6x3y) (7/9)ln(6x3y2) = x c , what's wrong with my working ?Welcome to Sarthaks eConnect A unique platform where students can interact with teachers/experts/students to get solutions to their queries Students (upto class 102) preparingAnswer (1 of 9) The two equations are mutually exclusive Im afraid, so there are no possible values (set both equations equal to each other, this is fine as both
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X 2 y 2 2y 4 2x y xy 4-Knowledgebase, relied on by millions of students &X^2y^23xy4xy^3=4 (x^2)(2y)(dy/dx) 2x(y^2) 3x(dy/dx) 3y 4x(3y^2)(dy/dx) 4y^3 = 0 dy/dx(2x^2 y) 3x 12x y^2) = 3y 2x(y^2) 4y^3 finish it up Reiny Respond to this Question First Name Your Response Similar Questions algebra 2 simplify(4xy^2)^3 Differential Equation what is the differential equation of (3x^22y^2)(1



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Ex 32, 4 Which of the following pairs of linear equations are consistent/ inconsistent?Graph 2x2y=4 2x − 2y = 4 2 x 2 y = 4 Solve for y y Tap for more steps Subtract 2 x 2 x from both sides of the equation − 2 y = 4 − 2 x 2 y = 4 2 x Divide each term by − 2 2 and simplify Tap for more steps Divide each term in − 2 y = 4 − 2 x 2 y = 4 2 x by − 2 2They both have slope 2 neither, their slopes are not the same and not opposite reciprocals How do you find perpendicular lines?
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2xy=3;x2y=4 This deals with linear equations with two unknowns Overview;First line 2x4y=2 Rearange 4y = 2 2x =>X2y=4;2xy=1 Simple and best practice solution for x2y=4;2xy=1 Check how easy it is, to solve this system of equations and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the system of equations solver your



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Y^{2}2yx^{2}2x\left(x^{2}2x\right)=\left(x^{2}2x\right) Subtract x^{2}2x from both sides of the equation y^{2}2y=\left(x^{2}2x\right) Subtracting x^{2}2x from itself leaves 0 y^{2}2y=x\left(x2\right) Subtract x^{2}2x from 0 y^{2}2y1^{2}=x\left(x2\right)1^{2} Divide 2, the coefficient of the x term, by 2 to get 1 Then add the square of 1 to both sides of theSimple and best practice solution for (4xxy^2)dx(yx^2y)dy=0 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the equation solver your own equation and let us solve it Equation SOLVE Solution for (4xxy^2)dx(yx^2y)dy=0Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology &



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Answer (1 of 3) First one uses the result that a^2b^2=(ab)(ab) In this case we have a=x2y, b=2(2xy)=4x2y So we get (x2y)^2(2(2xy))^2=(x2y(4x2y))(x2y4x2y) or (3x4y)(5x) In this case use the factorisation which is already given This saves a lot of workKnowledgebase, relied on by millions of students &See the answer See the answer See the answer done loading Show transcribed image text Expert Answer Who are the experts?



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Méétpfkwdmyntu join sab aa jao jaldi se nwdzvne)wid 29 July 9021o when the origin is shifted to (us) by the translationof axes, find theAre the graphs of the lines x – 2y = 4 and y = 2x – 2 parallel, perpendicular, or neither?Answer (1 of 2) The given equations represents three lines in a plane Let us represent the three line by L1, L2 and L3 Then, L1 ≡ 2x y 4 = 0 L2 ≡ 3x 2y 2 = 0 L3 ≡ x y 2 = 0 Clearly, none of the lines are parallel as can be observed from their slopes Now, L1 and L2 intersect



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Solve the differential equation (x^2 4xy 2y^2)dx (y^2 4xy 2x^2)dy = 0 asked in Differential equations by AmanYadav (557k points) differential equations;Graph y=x^22x4 Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for Tap for more steps Use the form , to find the values of , , and Consider the vertex form of a parabola Substitute the values of and into the formula Simplify the right side Tap for more steps Cancel the common factorAnswerx=0y=2Stepbystep explanation2x y =2 ( 1 )2y x= 4 ( 2 )(2) x 2 4y 2x =8 ( 3 )( 3 ) ( 1 )2x 2x y 4y = 2 85y = 10y = 10/5y=2by



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Answer (1 of 4) ye^(2x)dx=(4e^2x)dy or e^(2x)/(4e^2x)dx =1/yday or integof { e^2x/(4e^2x)}dx = integof (1/y)day or 1/2integof {2e^2x/(4e^2x)}dxArea inside x^2 2xy 4y^2 = 4 Natural Language;Views 1,478 Reply Answers and Replies #2 mfb



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Are the lines x− 2y= 4 and y= 2x − 2 parallel, perpendicular, or neither?Systemofequationscalculator 2x4y=2, 2xy =4 en Related Symbolab blog posts Middle School Math Solutions – Simultaneous Equations Calculator Solving simultaneous equations is one small2x2y=0 Geometric figure Straight Line Slope = 00/00 = 1000 xintercept = 0/1 = yintercept = 0/1 = Step by step solution Step 1 Pulling out like terms



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Answers The sides of triangle ABC are represented by yx =2, 2x y 4=0 and x 2y =4 The coordinates of c Find the coordinates of eth point of intersection of the lies 2xy3=0 and x2y4=0 If the line 2xsqrt(6)y=2 is a tangent to the hyperbola x^(2)2y^(2)=4 , then the coordinates of theLes solutions de l'équation différentielles sont les fonctions fdéfinies sur par f(x)=Ce2x C 2)On pose P(x) = ax 2 bxc ;Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology &



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Y = 1/2 1/2x Now we need to plot two or three points that lie on the line We need to find y at some x values At x = 1 , y = 1/2 (1/2*1)= 1/2 1/2 = 0 At x = 1 , y = 1/2 (1/2*1) = 1/2 1/2 = 1 Hence these areIf consistent, obtain the solution graphically (iii) 2x y – 6 = 0 , 4x – 2y – 4 = 0 2x y – 6 = 0 4x – 2y – 4 = 0 2x y – 6 = 0 Comparing with a1x b1y c1 = 0 ∴ a1 = 2 , b1 = 1 , c1 = –6 4x – 2y – 4 = 0 Comparing with a2x b2y c2 = 0 ∴ a2 = 4 , b2 = –2 , c2 = –4 a1 = 2Graph x^2y^22x2y2=0 x2 y2 2x − 2y − 2 = 0 x 2 y 2 2 x 2 y 2 = 0 Add 2 2 to both sides of the equation x2 y2 2x−2y = 2 x 2 y 2 2 x 2 y = 2 Complete the square for x2 2x x 2 2 x Tap for more steps Use the form a x 2 b



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Is x 2y 4 and y 2x 2 parallel?See the entire solution process below Step 1) Solve the first equation for x x 2y = 5 x 2y color(red)(2y) = 5 color(red)(2y) x 0 = 5 2y x = 5 2y Step 2) Substitute 5 2y for x in the second equation and solve for y 2x y = 4 becomes 2(5 2y) y = 4 (2 * 5) (2 * 2y) y = 4 10 4y y = 4 10 3y = 4 color(red)(10) 10 3y = color(red)(10) 4 0 3y = 6 3y =Knowledgebase, relied on by millions of students &



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