Yahoo Answers is my favorite site giving me an opportunity to help students and letting me keep in touch with math and physics which are the subjects of my interest Reading the answers of challenging problems given by subject experts adds to my knowledge This blog is a compilation of my selected answers given in YA! 函数y=sin (π/32x)cos2x的周期为,函数y=2cos^2x1的周期为 y=sin (π/32x)cos2x=√3/2 cos2x1/2sin2xcos2x = (√3/21) cos2x1/2sin2x, cos2x 和 sin2x的周期都是π, 所以原函数 周 期是π y=2cos^2x1=(1cos2x)1 = cos2x2, 该 函数周期是πSolve the equation √3 sin2x cos2x = 0 for π≤x≤π No idea how to approach this one Thanks a bunch for the help!
What Is The Integration Of The Root Of 1 Cos2x In The Limit 0 To 0pie Quora
